RESUME
M. Shanmugam
33, Thennolaikara 3rd street ,
Near South Krishnan Koil
Madurai – 625 001.
Ph: 93679-24654
Summary:
I, M. Shanmugam, Diploma Holder inComputer Skills %26amp;Applications .
Having more than 10 years of experience in Data Entry Operator *** Cashier and also Experience in Stores managemet. Ability to learn and upgrade new developments %26amp; Technologies.
Work Experience
Current Employment:
Organization : M/s. TVS-Motor Co. LTd. Authorised Dealer , Sathya JothiTvs
Designation : Spares Incharge/Cashier
Duration : From may-1996
Task and Responsibility
q Maintaining Spares Purchase Order through SAP/DMS
q Maintaining good Inventory Management .
q Sending the reports to Areo Office
q Arrangement of spares to solve the customer problem.
Previous Employment:
Organization : M/s. Cheema Motors Pvt. Ltd., Madurai
Designation : Computer Operator .
Duration : From may 94 to april-1996
Task and Responsibility
q New Vehicle Billing and Vehicle Service Billing arrangement.
q Dealer Network Relation
q Maintaining good communication with ASC (Authorised Service Centre)
q
Organization : M/s. Madurai Institute of Computers.
Designation : Computer Instructor
Duration : May 1993 to april 1994
Task and Responsibility
q Learn and Teaching for Basic Concept of Computers
q Preventive Maintanance for Computers
q
Computer Skills
Software
Operating Systems : Windows
Package : Ms – Office 2000
Internet Handling : Well Known
Educational Qualification
Higher Secondary Completed 1992
q D.C.S.A, (Diploma in Computer Skills %26amp; Applications)
Jeevana Jyothi Computer Training Programme
The American College , Madurai ..
Rashtrabasha Completed through Hindi Language (Board Of Hindi Prachara Sabha)
Lower Grade Completed English Typewriting (Tamilnadu Technical Board)
Personal Information
Age %26amp; Date of Birth : 35 Years %26amp;15th June1971
Language Known : English, Tamil
Nationality : Indian
Marital Status : Married
Physcical Disablled : Orthopeadic Handicapped in Left Leg
Address for Communication : No33, Thennolaikara 3rd Lane ,Near South Krishnan koil
Madurai – 625 001.
Declaration
I hereby declare that all the above mentioned details are true to the best of my knowledge and belief.
Place : Madurai
Date :15 .08.2006 M. Shanmugam
I have attached my cvs please consider of job request?
If you want to apply for a job at Yahoo, you need to follow correct application process. From the Home page of Yahoo, click on the "jobs" link all the way at the bottom of the page, and follow the links from there.
Good luck!
Reply:You are welcome.
Reply:put your CV on naukery.com, timesjob.com
Reply:This is not a right place !!!!! Put ur CV at naukri.com/monsterindia.com
Reply:www.myjobseye.co.ke
Monday, May 24, 2010
Abstract Algebra?
Theorem: Let T be a linear operator on a finite-dimensional vector space such that the characteristic polynomial of T splits. Suppose that b is an eigenvalue of T with multiplicity m. Then dim(K_b) %26lt;= m.
Proof: Let W = K_b, and let h(t) be the characteristic polynomial of T_w. By theorem h(t) divides the characteristic polynomial of T, and by Theorem **, b is the only eigenvalue of T_w. Hence, h(t) = (-1)^d(t-b)^b, where d = dim(W), and d%26lt;=m.
Theorem ** : Let T be a linear operator on a vector space V, and let b be an eignevalue of T. Then
For any scalar c not equal to b, the restriction of T- cI to K_b is one-to-one.
Note: 'I' is the identity transformation. Also K_b is the generalized eigenspace of T corresponding to b.
What I need help on is on the the proof, I don't understand why is it that it can be concluded from theorem** that b is the ONLY eigenvalue of T_w, or even that it is an eigenvalue for that matter. If someone could explain, it would be helpful.
Abstract Algebra?
Suppose that b' ≠ b is another eigenvalue of T_w. Theorem (**) then asserts that T - b'I restricted to K_b is injective, which means that its kernel is {0}, so b' cannot be an eigenvalue (remember that an eigenspace is always ≠ {0}).
Regarding the second part of your question, b is, by hypothesis, an eigenvalue of T, so it's also an eigenvalue of T_w, because K_b is an invariant subspace for T.
Hope this helps.
Proof: Let W = K_b, and let h(t) be the characteristic polynomial of T_w. By theorem h(t) divides the characteristic polynomial of T, and by Theorem **, b is the only eigenvalue of T_w. Hence, h(t) = (-1)^d(t-b)^b, where d = dim(W), and d%26lt;=m.
Theorem ** : Let T be a linear operator on a vector space V, and let b be an eignevalue of T. Then
For any scalar c not equal to b, the restriction of T- cI to K_b is one-to-one.
Note: 'I' is the identity transformation. Also K_b is the generalized eigenspace of T corresponding to b.
What I need help on is on the the proof, I don't understand why is it that it can be concluded from theorem** that b is the ONLY eigenvalue of T_w, or even that it is an eigenvalue for that matter. If someone could explain, it would be helpful.
Abstract Algebra?
Suppose that b' ≠ b is another eigenvalue of T_w. Theorem (**) then asserts that T - b'I restricted to K_b is injective, which means that its kernel is {0}, so b' cannot be an eigenvalue (remember that an eigenspace is always ≠ {0}).
Regarding the second part of your question, b is, by hypothesis, an eigenvalue of T, so it's also an eigenvalue of T_w, because K_b is an invariant subspace for T.
Hope this helps.
Abstract Algebra?
I have two questions, which I think are harder then I think.
1) Let V be a finite-dimensional inner product space, and let T be a linear operator on V. Prove that if T is invertible, then T* is invertible and (T*)^-1 = (T^-1)*.
What I have done is:
TT^(-1) = I = T^(-1)T
Taking the adjoint of all the sides I get:
[T^(-1)]*t* = I* = I = T*[T^(-1)]; I'm using the property (TU)* = T*U*
Which then shows that T* is invertible and its easy to finish it off. But I'm wondering what I did is actually correct, b/c then it would be really easy, and I feel theres more to it.
2) For a linear operator T on an inner product space V, prove that T*T = T_0 implies T = T_0. Is the same result true if we assume that TT* = T_0?
And well this one I'm just having troubles with and really don't know how to do it, I thought of multiplying both sides by T^(-1) but I don't know whether T is invertible.
Help would be greatly appreciated =)
Abstract Algebra?
1. You did the hard work. I'd just make it a little clearer:
[T^(-1)]* T* = [T T^(-1) ]*= I* = I .
T* [T^(-1)]* = [T^(-1) T]*= I* = I .
Thus [T^(-1)]* is both a left and right inverse for T*.
2. I assume that T_0 is supposed to be the linear transformation that maps everything to 0.
If T*T = T_0, then for every x, 0 = x* T* T x = || Tx ||², so Tx=0.
Hence T = T_0.
If TT* = T_0, the same argument proves that T* = T_0. Question for you: does that imply that T = T_0?
1) Let V be a finite-dimensional inner product space, and let T be a linear operator on V. Prove that if T is invertible, then T* is invertible and (T*)^-1 = (T^-1)*.
What I have done is:
TT^(-1) = I = T^(-1)T
Taking the adjoint of all the sides I get:
[T^(-1)]*t* = I* = I = T*[T^(-1)]; I'm using the property (TU)* = T*U*
Which then shows that T* is invertible and its easy to finish it off. But I'm wondering what I did is actually correct, b/c then it would be really easy, and I feel theres more to it.
2) For a linear operator T on an inner product space V, prove that T*T = T_0 implies T = T_0. Is the same result true if we assume that TT* = T_0?
And well this one I'm just having troubles with and really don't know how to do it, I thought of multiplying both sides by T^(-1) but I don't know whether T is invertible.
Help would be greatly appreciated =)
Abstract Algebra?
1. You did the hard work. I'd just make it a little clearer:
[T^(-1)]* T* = [T T^(-1) ]*= I* = I .
T* [T^(-1)]* = [T^(-1) T]*= I* = I .
Thus [T^(-1)]* is both a left and right inverse for T*.
2. I assume that T_0 is supposed to be the linear transformation that maps everything to 0.
If T*T = T_0, then for every x, 0 = x* T* T x = || Tx ||², so Tx=0.
Hence T = T_0.
If TT* = T_0, the same argument proves that T* = T_0. Question for you: does that imply that T = T_0?
Abstract Algebra?
T is a linear operator on the vector space V, find an ordered basis for the T-cyclic subspace generated by the vector z.
V = R^4, T(a, b, c, d) = (a + b, b - c, a + c, a+ d) and z = (1, 0, 0, 0)
Solution:
Let W be the T-cyclic subspace generated by z and β its basis.
W = {z, T(z), T²(z)....}
Therefore,
z = (1, 0, 0, 0)
T(z) = (1, 0, 1, 1)
T²(z) = (1, -1, 2, 2)
T³(z) = (0, -3, 3, 3)
T^4(z) = (-3, -6, 3, 3)
T^5(z) = -(-9, -9, 0, 0)
T^6(z) = (-18, -9, -9, -9)
T^7(z) = (-27, 0, -27, -27)
T^8(z) = (-27, -27, -54, -54)
So obviously they have begun to repeat as multiples of the first 7 elements in W. The back of th text says that β = {(1, 0, 0, 0), (1, 0, 1, 1), (1, -1, 2, 2)} which means that dim(W) = 3 but doesnt that necessarily mean that there should only be three coordinates being "used" in each of the points rather then 4? And how is it that you check that the basis will span W when I dont see a general way of expressing the elements in W?
Thank you
Abstract Algebra?
T^3(z) = 0 z -3 T(z) + 3 T^2(z)
So you can get T^3 form the first 3.
But that means you can get them all from the first 3!
T^4z = T T^3 z = 0 T(z) - 3 T^2(z) + 3 T^3 (z) =
- 3 T^2(z) + 3 ( -3 T(z) + 3 T^2(z)) = -9 T(z) + 6T^2(z)
etc. Each time apply T once more and reexpress T^3(z) using the first formula I showed.
All powers T^n(z) are linear combinations of z, T(z), and T^2(z), which is what you are supposed to prove.
Its a three dimensional subspace of a 4-dimensional space.
local florist
V = R^4, T(a, b, c, d) = (a + b, b - c, a + c, a+ d) and z = (1, 0, 0, 0)
Solution:
Let W be the T-cyclic subspace generated by z and β its basis.
W = {z, T(z), T²(z)....}
Therefore,
z = (1, 0, 0, 0)
T(z) = (1, 0, 1, 1)
T²(z) = (1, -1, 2, 2)
T³(z) = (0, -3, 3, 3)
T^4(z) = (-3, -6, 3, 3)
T^5(z) = -(-9, -9, 0, 0)
T^6(z) = (-18, -9, -9, -9)
T^7(z) = (-27, 0, -27, -27)
T^8(z) = (-27, -27, -54, -54)
So obviously they have begun to repeat as multiples of the first 7 elements in W. The back of th text says that β = {(1, 0, 0, 0), (1, 0, 1, 1), (1, -1, 2, 2)} which means that dim(W) = 3 but doesnt that necessarily mean that there should only be three coordinates being "used" in each of the points rather then 4? And how is it that you check that the basis will span W when I dont see a general way of expressing the elements in W?
Thank you
Abstract Algebra?
T^3(z) = 0 z -3 T(z) + 3 T^2(z)
So you can get T^3 form the first 3.
But that means you can get them all from the first 3!
T^4z = T T^3 z = 0 T(z) - 3 T^2(z) + 3 T^3 (z) =
- 3 T^2(z) + 3 ( -3 T(z) + 3 T^2(z)) = -9 T(z) + 6T^2(z)
etc. Each time apply T once more and reexpress T^3(z) using the first formula I showed.
All powers T^n(z) are linear combinations of z, T(z), and T^2(z), which is what you are supposed to prove.
Its a three dimensional subspace of a 4-dimensional space.
local florist
Hr block bad experience. can i go to another branch?
can i go to another branch? the branches seem independent of eachother, like mompop shops with the hr logo pasted on front. i get this impression because no matter what extension or number i try to call,i get an operator ready to connect me to a branch.it took 3.5 hrs to do a joint return, $417. with 2 schedule c's, i waited 1hour for another hr block associate to explain to my acct that a depreciation (on schedule c) goes only in the depreciation column and the FULL AMOUNT does not go into a category also. (eg. suppplies). i am now on my 3rd trip to revising a 1040x, the numbers are only off a dollar, BUT the part 2 explanation seems poor which reads " CLIENT REQUEST THE ROYALTIES BE REMOVED FROM THE SCHEDUEL E AND PUT ON SCHEDUEL C" yes schedule is spelled wrong twice. so can i go to another branch? call another number? was i wrong to explain what the royalties were for then later find that they need be self employment taxed and request 1040x ? does a new 1040 need be attached
Hr block bad experience. can i go to another branch?
I've talked to enrolled agents about Block. A few are with Block, but many leave there. But, by and large, Block is NOT a place to go if you need your income taxes done. You need an enrolled agent. If your return is complicated, look up an enrolled agent on the National Association of Enrolled Agents website. Click on "find an enrolled agent". Type in your city, town, State or zip. Enrolled Agents are professional tax practitioners who have technical expertise
in the field of taxation and are licensed to represent taxpayers at all administrative levels before the Internal Revenue Service. Moreover, Enrolled Agents are the only tax professionals who are required by the IRS to maintain their expertise through continuing professional education. Block has to vacate their boiler room. Firstly, the firm is not to print the SS# of the client on any of the Tax software they send out.
Secondly, they work with the IRS to cheat the taxpayer. This happened to me before I became familiar with the IRC, went to seminars, then passed the rigorous enrolled agent examination.
Reply:You can request another preparer (ask for a very experienced one) at the same office or, if they can't find you one, they will check in other offices nearby. Or you can just ask another preparer to do a review of your taxes. Talk to office manager anyway - she/he may come up with some other solution. If your tax preparer demonstrated incompetence and you complain, you can expect your tax prep fee to be reduced.
Reply:If I were you, I'd ditch H%26amp;R Block and go to a CPA. H%26amp;R does OK with straightforward stuff, but it sounds like your situation is really out of their league. Just going to another branch will very likely lead to a repeat of the situation unless you happen to get really lucky.
Reply:If you are not happy, go to another branch.
You generally report royalties in Part I of Schedule E (Form 1040), Supplemental Income and Loss. However, if you hold an operating oil, gas, or mineral interest or are in business as a self-employed writer, inventor, artist, etc., report your income and expenses on Schedule C.
Don't expect THEM to be happy though. H%26amp;R Block owns some of the branches, the others are franchised out to individual owners (they only get the use of the name, software and TV advertising).
So Momma Jones ain't gonna be too happy to clean up a mess made by Momma Mabel. Mabel already has all your money! Momma Jones will be working for FREE!
I did taxes for them several years ago. They gave us a 40 hour crash course ( a couple hours a day for about 20 days) and then called us experts. I'm sure that hasn't changed much.
Complain to the main office and they'll send you an apology and a coupon for $20 off next year's preparation fee.
The incorrect spelling will not affect your tax return.
Reply:why did you request to have royalties put on schedule C?
Reply:instead of going to the office you can go online at taxcut.com and do your own taxes with the same program that H %26amp; R Block uses and it wont cost you to file your return.
Reply:Ask for a senior tax pro to look at your return. Senior tax pros are usually very experienced and are often enrolled agents. Sorry you have had this difficulty, but call the office and ask for their most experienced senior tax pro.
Hr block bad experience. can i go to another branch?
I've talked to enrolled agents about Block. A few are with Block, but many leave there. But, by and large, Block is NOT a place to go if you need your income taxes done. You need an enrolled agent. If your return is complicated, look up an enrolled agent on the National Association of Enrolled Agents website. Click on "find an enrolled agent". Type in your city, town, State or zip. Enrolled Agents are professional tax practitioners who have technical expertise
in the field of taxation and are licensed to represent taxpayers at all administrative levels before the Internal Revenue Service. Moreover, Enrolled Agents are the only tax professionals who are required by the IRS to maintain their expertise through continuing professional education. Block has to vacate their boiler room. Firstly, the firm is not to print the SS# of the client on any of the Tax software they send out.
Secondly, they work with the IRS to cheat the taxpayer. This happened to me before I became familiar with the IRC, went to seminars, then passed the rigorous enrolled agent examination.
Reply:You can request another preparer (ask for a very experienced one) at the same office or, if they can't find you one, they will check in other offices nearby. Or you can just ask another preparer to do a review of your taxes. Talk to office manager anyway - she/he may come up with some other solution. If your tax preparer demonstrated incompetence and you complain, you can expect your tax prep fee to be reduced.
Reply:If I were you, I'd ditch H%26amp;R Block and go to a CPA. H%26amp;R does OK with straightforward stuff, but it sounds like your situation is really out of their league. Just going to another branch will very likely lead to a repeat of the situation unless you happen to get really lucky.
Reply:If you are not happy, go to another branch.
You generally report royalties in Part I of Schedule E (Form 1040), Supplemental Income and Loss. However, if you hold an operating oil, gas, or mineral interest or are in business as a self-employed writer, inventor, artist, etc., report your income and expenses on Schedule C.
Don't expect THEM to be happy though. H%26amp;R Block owns some of the branches, the others are franchised out to individual owners (they only get the use of the name, software and TV advertising).
So Momma Jones ain't gonna be too happy to clean up a mess made by Momma Mabel. Mabel already has all your money! Momma Jones will be working for FREE!
I did taxes for them several years ago. They gave us a 40 hour crash course ( a couple hours a day for about 20 days) and then called us experts. I'm sure that hasn't changed much.
Complain to the main office and they'll send you an apology and a coupon for $20 off next year's preparation fee.
The incorrect spelling will not affect your tax return.
Reply:why did you request to have royalties put on schedule C?
Reply:instead of going to the office you can go online at taxcut.com and do your own taxes with the same program that H %26amp; R Block uses and it wont cost you to file your return.
Reply:Ask for a senior tax pro to look at your return. Senior tax pros are usually very experienced and are often enrolled agents. Sorry you have had this difficulty, but call the office and ask for their most experienced senior tax pro.
Help!! bought a samsung sgh-i600 w/o contract. Cannot use the phone with HK SIM card. Why?
i used phone in singapore with my singtel prepaid card - ok
in hk, i get the csl network/ 3G but cannot call out or receive calls, or phone freezes.
i have tried without success:
a) change the operator settings - present choice: singtel, starhub, m1
b) called samsung support from hk
c) change a new csl international sim card
d) checked with the shop i bought the phone - refer me to samsung support
e) find help from forums on the net - no luck
Q: does singtel preset some settings on the phone they sell? if so, what number to call for assistance?
i am now in hk. thanks v v v v v much.
Help!! bought a samsung sgh-i600 w/o contract. Cannot use the phone with HK SIM card. Why?
try this... if the hk you are talking about is hong kong... if not use this...
Reply:You make sure your samsung phone is
GSM one! if it is, you turn to online sim card experts at http://www.pandasim.com/
in hk, i get the csl network/ 3G but cannot call out or receive calls, or phone freezes.
i have tried without success:
a) change the operator settings - present choice: singtel, starhub, m1
b) called samsung support from hk
c) change a new csl international sim card
d) checked with the shop i bought the phone - refer me to samsung support
e) find help from forums on the net - no luck
Q: does singtel preset some settings on the phone they sell? if so, what number to call for assistance?
i am now in hk. thanks v v v v v much.
Help!! bought a samsung sgh-i600 w/o contract. Cannot use the phone with HK SIM card. Why?
try this... if the hk you are talking about is hong kong... if not use this...
Reply:You make sure your samsung phone is
GSM one! if it is, you turn to online sim card experts at http://www.pandasim.com/
Answer math question = TEN points! (correct though)?
1. On Saturn, the inhabitants use the same mathematical operators that we do (+,-,etc), and they also use an operator @ that we do not know. Scientist have also determined that the following is true for any real numbers x and y:
x@0 = x
x@y = y@x
(x + 1)@y = (x@y) + y + 1
1. What is the value of 12@5?
a. 53 b.59 c.65 d.71 e.77
2. On a school trip to Saturn you must solve the equation 5@x = 17 in order to return to Earth. Under the same conditions as in the statement in question 1 above what is the value of x?
a.1 b.2 c.3 d.4 e.5
Answer math question = TEN points! (correct though)?
1
1@5 = 0@5 + 5 + 1 = 5@0 + 6 = 5 + 6 = 11
2@5 = 1@5 + 6 = 11 + 6 = 17
3@5 = 2@5 + 6 = 17 + 6 = 23
so n@5 = 5 + 6n, and 12@5 = 5 + 72 = 77
2
1@x = 0@x + x + 1 = x@0 + x + 1 = 2x + 1
2@x = 1@x + x + 1 = (2x + 1) + x + 1 = 3x + 2
looks like n@x = (n+1)x + n
so 5@x = 6x + 5 = 17, 6x = 12, x = 2
x@0 = x
x@y = y@x
(x + 1)@y = (x@y) + y + 1
1. What is the value of 12@5?
a. 53 b.59 c.65 d.71 e.77
2. On a school trip to Saturn you must solve the equation 5@x = 17 in order to return to Earth. Under the same conditions as in the statement in question 1 above what is the value of x?
a.1 b.2 c.3 d.4 e.5
Answer math question = TEN points! (correct though)?
1
1@5 = 0@5 + 5 + 1 = 5@0 + 6 = 5 + 6 = 11
2@5 = 1@5 + 6 = 11 + 6 = 17
3@5 = 2@5 + 6 = 17 + 6 = 23
so n@5 = 5 + 6n, and 12@5 = 5 + 72 = 77
2
1@x = 0@x + x + 1 = x@0 + x + 1 = 2x + 1
2@x = 1@x + x + 1 = (2x + 1) + x + 1 = 3x + 2
looks like n@x = (n+1)x + n
so 5@x = 6x + 5 = 17, 6x = 12, x = 2
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