In an "if" line - how do I use NOT (!) properly? I wanted to make a program that would ask the user to input a number other than 4? It would have if !4 it would say well done and and ELSE that says that they have entered 4. Basically I want to see how you use the boolean operator ! :-D
C++ Help With "If" Statements?
#include%26lt;iostream%26gt;
using namespace::std
void main(){
cout%26lt;%26lt;"Plz enter a number"%26lt;%26lt;endl;
int x;
cin%26gt;%26gt;x;
if(x!=4)
{
cout%26lt;%26lt;"Well Done"%26lt;%26lt;endl;
}
else {
cout%26lt;%26lt;"The Number You Entered is 4"%26lt;%26lt;endl;
}
};
I GUESS THIS IS WHAT YOU MEAN. YOU DONT NEED A BOOLEAN OPERATOR IN THIS CASE.
Reply:#include%26lt;stdio.h%26gt;
int main(void)
{
int a, b;
if (a = 1; a %26gt; 0; a--)
{
printf("Give me your number please");
scanf("%d", %26amp;b);
if (b != 4) // or (b %26lt;%26gt; 4)
printf("Well Done");
else
printf("Wrong number!");
}
return 0;
}
I'm not sure tho, it's been a while since i've used C;)
Reply:if (x !=4)
printf("welldone");
else
printf("you have entered 4");
the rest of the coding is up to u
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